4.3 Exercise B Part 2
myCBSEguide App
CBSE, NCERT, JEE Primary, NEET-UG, NDA, Exam Papers, Question Bank, NCERT Solutions, Exemplars, Revision Notes, Costless Videos, MCQ Tests & more.
Install NowNCERT Solutions form 12 Maths Exercise four.iii Class 12 Maths book solutions are bachelor in PDF format for free download. These ncert book affiliate wise questions and answers are very helpful for CBSE lath examination. CBSE recommends NCERT books and most of the questions in CBSE exam are asked from NCERT text books. Grade 12 Maths chapter wise NCERT solution for Maths part ane and Maths function ii for all the chapters can be downloaded from our website and myCBSEguide mobile app for free.
Download NCERT solutions for Determinants as PDF
NCERT Solutions class 12 Maths Determinants
i. Find the expanse of the triangle with vertices at the points given in each of the post-obit:
(i) (1, 0), (6, 0), (4, 3)
(2) (2, 7), (1, 1), (10, 8)
(iii) 
Ans. (i) Surface area of triangle = Modulus of 
= 
= 
= 
= 
= 
sq. units
(2) Surface area of triangle = Modulus of = 
= 
= 
= 
= 
= 
= 
sq. units
(iii) Area of triangle = Modulus of = 
= 
= 
= 
= 
= 
= 15 sq. units
NCERT Solutions class 12 Maths Do 4.three
two. Show that the points A 
B 
C 
are collinear.
Ans. Area of triangle ABC = Modulus of = 
= 
= 
= 
= 
= 0
Therefore, points A, B and C are collinear.
NCERT Solutions class 12 Maths Exercise 4.3
iii. Find values of 
if area of triangle is 4 sq. units and vertices are:
(i) 
(ii) 
Ans. (i) Given: Surface area of triangle = Modulus of = 4
Modulus of 
= 4
Taking positive sign, 
Taking negative sign, 
(ii) Given: Area of triangle = Modulus of = 4
= 4
Taking positive sign,
Taking negative sign,
NCERT Solutions form 12 Maths Exercise 4.3
4. (i) Find the equation of the line joining (1, 2) and (3, 6) using determinants.
(ii) Find the equation of the line joining (3, ane) and (9, 3) using determinants.
Ans. (i) Permit P
be any bespeak on the line joining the points (1, 2) and (3, half-dozen).
So, Surface area of triangle that could be formed by these points is zero.
Area of triangle = Modulus of = 0
Modulus of 
= 0
which is required line.
(ii) Let P be any point on the line joining the points (3, 1) and (9, 3).
Then, Area of triangle that could exist formed by these points is naught.
Area of triangle = Modulus of = 0
Modulus of 
= 0
which is required line.
NCERT Solutions class 12 Maths Exercise iv.three
v. If area of triangle is 35 sq. units with vertices 
and 
And so is:
(A) 12
(B) 
(C) 
(D) 
Ans. Given: Area of triangle = Modulus of = 35
Modulus of 
= 35
Taking positive sign, 
Taking negative sign, 
Therefore, option (D) is correct.
NCERT Solutions class 12 Maths Exercise 4.three
NCERT Solutions Form 12 Maths PDF (Download) Free from myCBSEguide app and myCBSEguide website. Ncert solution form 12 Maths includes text book solutions from both role 1 and role 2. NCERT Solutions for CBSE Class 12 Maths have total 20 chapters. 12 Maths NCERT Solutions in PDF for free Download on our website. Ncert Maths class 12 solutions PDF and Maths ncert class 12 PDF solutions with latest modifications and every bit per the latest CBSE syllabus are but available in myCBSEguide
CBSE App for Class 12
To download NCERT Solutions for class 12 Physics, Chemistry, Biology, History, Political Science, Economics, Geography, Information science, Dwelling Scientific discipline, Accountancy, Business Studies and Dwelling Science; do cheque myCBSEguide app or website. myCBSEguide provides sample papers with solution, test papers for affiliate-wise practice, NCERT solutions, NCERT Exemplar solutions, quick revision notes for ready reference, CBSE estimate papers and CBSE important question papers. Sample Newspaper all are made bachelor throughthe all-time app for CBSE students and myCBSEguide website.
4.3 Exercise B Part 2,
Source: https://mycbseguide.com/blog/ncert-solutions-class-12-maths-exercise-4-3/
Posted by: cortezsorm2002.blogspot.com
0 Response to "4.3 Exercise B Part 2"
Post a Comment